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wordy, and the writer s purpose is unclear To start revising it, look for a BOY S FAN word Not there Thus you know the problem isn t that the sentence is compound It s complicated It starts simply enough with a traditional structure of subject/verb/object:

// Search strings using System; class StringSearchDemo { static void Main() { string str = "C# has powerful string handling"; int idx; ConsoleWriteLine("str: " + str); idx = strIndexOf('h'); ConsoleWriteLine("Index of first 'h': " + idx); idx = strLastIndexOf('h'); ConsoleWriteLine("Index of last 'h': " + idx); idx = strIndexOf("ing", StringComparisonOrdinal); ConsoleWriteLine("Index of first \"ing\": " + idx); idx = strLastIndexOf("ing", StringComparisonOrdinal); ConsoleWriteLine("Index of last \"ing\": " + idx);

Part II:

Now you will see why our new definition of logarithm is so convenient If we want to differentiate the logarithm function, we can apply the Fundamental Theorem of Calculus: d d ln x = dx dx

char[] chrs = { 'a', 'b', 'c' }; idx = strIndexOfAny(chrs); ConsoleWriteLine("Index of first 'a', 'b', or 'c': " + idx); if(strStartsWith("C# has", StringComparisonOrdinal)) ConsoleWriteLine("str begins with \"C# has\""); if(strEndsWith("ling", StringComparisonOrdinal)) ConsoleWriteLine("str ends with \"ling\""); } }

The output from the program is shown here:

str: C# has powerful string handling Index of first 'h': 3 Index of last 'h': 23 Index of first "ing": 19 Index of last "ing": 28 Index of first 'a', 'b', or 'c': 4 str begins with "C# has" str ends with "ling"

d d d ln( 4 + x) , ln( x 3 x) , ln( cos x) , dx dx dx d d [( ln x) ( cot x) ] ( ln x) 5 , dx dx

A string search method that you will find useful in many circumstances is Contains( ) Its general form is shown here: public bool Contains(string value) It returns true if the invoking string contains the string specified by value, and false otherwise It uses ordinal searching This method is especially useful when all you need to know is if a specific substring exists within another string Here is an example that demonstrates its use

// Demonstrate Contains() using System; class ContainsDemo { static void Main() { string str = "C# combines power with performance"; if(strContains("power")) ConsoleWriteLine("The sequence power was found"); if(strContains("pow")) ConsoleWriteLine("The sequence pow was found"); if(!strContains("powerful")) ConsoleWriteLine("The sequence powerful was not found"); } }

The output is shown here:

If you chose, you could stop there Note that the sentence continues with a series of prepositional and other phrases:

22:

For the first problem, we let u = 4 + x and du/dx = 1 Therefore, we have 1 d 1 d ln( 4 + x) = ( 4 + x) = dx 4 + x dx 4+x Similarly, d 1 3x 2 1 d 3 ln( x 3 x) = 3 ( x x) = 3 dx x x dx x x 1 d sin x d ln( cos x) = ( cos x) = dx cos x dx cos x 5( ln x) 4 d 1 d ( ln x) = 5( ln x) 4 = ( ln x) 5 = 5( ln x) 4 dx dx x x d d d ln x ( cot x) + ( ln x) cot x ( ln x) ( cot x) = dx dx dx = 1 cot x + ( ln x) ( csc2 x) x

As the output shows, Contains( ) searches for a matching sequence, not for whole words Thus, both pow and power are found However, because there are no sequences that match powerful , it is (correctly) not found Several of the search methods have additional forms that allow you to begin a search at a specified index or to specify a range to search within All versions of the String search methods are shown in Table 22-3

Method public bool Contains(string value) public bool EndsWith(string value) public bool EndsWith(string value, StringComparison comparisonType) public bool EndsWith(string value, bool ignoreCase, CultureInfo culture) public int IndexOf(char value) public int IndexOf(string value)

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YOU TRY IT What is the derivative of the function ln( x3 + x2 )