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There is one important thing to notice in this output: the empty string that occurs between land and two This is caused by the fact that in the original string, the word land is followed by a comma and a space, as in land, two However, both the comma and the space are specified as separators Thus, when this string is split, the empty string that exists between the two separators (the comma and the space) is returned There are several additional forms of Split( ) that take a parameter of type StringSplitOptions This parameter controls whether empty strings are part of the resulting split Here are these forms of Split( ): public string[ ] Split(char[ ] separator, StringSplitOptions options) public string[ ] Split(string[ ] separator, StringSplitOptions options) public string[ ] Split(char[ ] separator, int count , StringSplitOptions options) public string[ ] Split(string[ ] separator, int count , StringSplitOptions options) The first two forms split the invoking string into pieces and return an array containing the substrings The characters that delimit each substring are passed in separator If separator is null, then whitespace is used as the separator In the third and fourth forms, no more than count substrings will be returned For all versions, the value of options determines how to handle empty strings that result when two separators are adjacent to each other The StringSplitOptions enumeration defines only two values: None and RemoveEmptyEntries If options is None, then empty strings are included in the result (as the previous program showed) If options is RemoveEmptyEntries, empty strings are excluded from the result To understand the effects of removing empty entries, try replacing this line in the preceding program:

string[] parts = strSplit(seps);

exp( ln a + ln b) and ln( 7 [exp( c) ])

C# defines the following arithmetic operators:

I have reviewed your letter of complaint explaining the dif culties you had (twelve words)

Operator + * / % ++ Meaning Addition Subtraction (also unary minus) Multiplication Division Modulus Increment Decrement

The operators +, , *, and / all work in the expected way These can be applied to any builtin numeric data type Although the actions of arithmetic operators are well known to all readers, a few special situations warrant some explanation First, remember that when / is applied to an integer, any remainder will be truncated; for example, 10/3 will equal 3 in integer division You can obtain the remainder of this division by using the modulus operator, % The % is also referred to as the remainder operator It yields the remainder of an integer division For example, 10 % 3 is 1 In C#, the % can be applied to both integer and floating-point types Thus, 100 % 30 is also 1 (This differs from C/C++, which allow modulus operations only on integer types) The following program demonstrates the modulus operator

We use the key property that the exponential function is the inverse of the logarithm function We have exp( ln a + ln b) = exp( ln( a b) ) = a b, ln( 7 [exp( c) ]) = ln 7 + ln( exp( c) ) = ln 7 + c

Part I:

// Demonstrate the % operator using System; class ModDemo { static void Main() { int iresult, irem; double dresult, drem; iresult = 10 / 3; irem = 10 % 3; dresult = 100 / 30; drem = 100 % 30; ConsoleWriteLine("Result and remainder of 10 / 3: " + iresult + " " + irem); ConsoleWriteLine("Result and remainder of 100 / 30: " + dresult + " " + drem); } }

The output from the program is shown here:

Result and remainder of 10 / 3: 3 1 Result and remainder of 100 / 30: 333333333333333 1

YOU TRY IT Simplify the expression ln( a3 35 5 4 )

Introduced in 2, the ++ and the are the increment and decrement operators As you will see, they have some special properties that make them quite interesting Let s begin by reviewing precisely what the increment and decrement operators do The increment operator adds 1 to its operand, and the decrement operator subtracts 1 Therefore,

x = x + 1;

Or here:

x++;