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// Tokenize strings using System; class TokenizeDemo { static void Main() { string[] input = { "100 + 19", "100 / 33", "-3 * 9", "100 - 87" }; char[] seps = {' '}; for(int i=0; i < inputLength; i++) { // split string into parts string[] parts = input[i]Split(seps); ConsoleWrite("Command: "); for(int j=0; j < partsLength; j++) ConsoleWrite(parts[j] + " "); ConsoleWrite(", Result: "); double n = DoubleParse(parts[0]); double n2 = DoubleParse(parts[2]); switch(parts[1]) { case "+": ConsoleWriteLine(n break; case "-": ConsoleWriteLine(n break; case "*": ConsoleWriteLine(n break; case "/": ConsoleWriteLine(n break; } } } }

+ n2);

- n2);

Now we want to learn some calculus properties of our new function exp(x) These are derived from the standard formula for the derivative of an inverse, as in Section 251 For all x we have d (exp(x)) = exp(x) dx In other words, exp(x) dx = exp(x) More generally, du d exp(u) = exp(u) dx dx and exp(u) du dx = exp(u) + C dx

* n2);

/ n2);

22:

I have reviewed your letter of complaint explaining the dif culties you had in registering your company s representatives for the National Widget Conference and Trade Show (twenty- ve words)

We note for the record that the exponential function is the only function (up to constant multiples) that is its own derivative This fact will come up later in our applications of the exponential

Here is the output:

Command: Command: Command: Command: 100 + 19 , Result: 119 100 / 33 , Result: 303030303030303 -3 * 9 , Result: -27 100 - 87 , Result: 13

Beginning with NET Framework 40, the following additional forms of Join( ) are also defined: public static string Join(string separator, params object[ ] values) public static string Join(string separator, IEnumerable<string>[ ] values) public static string Join<T>(string separator, IEnumerable<T>[ ] values) The first form returns a string that contains the concatenation of the string representation of the objects in values The second form returns a string that contains the concatenation of the collection of strings referred to by values The third form returns a string that contains the concatenation of the string representation of the collection of objects in values In all cases, each string is separated from the next by separator

.

For the first problem, notice that u = 4x hence du/dx = 4 Therefore we have d d exp( 4x) = [exp( 4x) ] ( 4x) = 4 exp( 4x) dx dx

Sometimes you will want to remove leading and trailing spaces from a string This type of operation, called trimming, is often needed by command processors For example, a database might recognize the word print However, a user might enter this command with one or more leading or trailing spaces Any such spaces must be removed before the string can be recognized by the database Conversely, sometimes you will want to pad a string with spaces so that it meets some minimal length For example, if you are preparing formatted output, you might need to ensure that each line is a certain length in order to maintain an alignment Fortunately, C# includes methods that make these types of operations easy To trim a string, use one of these Trim( ) methods: public string Trim( ) public string Trim(params char[ ] trimChars) The first form removes leading and trailing whitespace from the invoking string The second form removes leading and trailing occurrences of the characters specified by trimChars In both cases, the resulting string is returned You can pad a string by adding characters to either the left or the right side of the string To pad a string on the left, use one of the methods shown here: public string PadLeft(int totalWidth) public string PadLeft(int totalWidth, char paddingChar) The first form adds spaces on the left as needed to the invoking string so that its total length equals totalWidth The second form adds the character specified by paddingChar as needed to the invoking string so that its total length equals totalWidth In both cases, the resulting string is returned If totalWidth is less than the length of the invoking string, a copy of the invoking string is returned unaltered To pad a string to the right, use one of these methods: public string PadRight(int totalWidth) public string PadRight(int totalWidth, char paddingChar).

Part II: