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Here, lockObj is a reference to the object being synchronized If you want to synchronize only a single statement, the curly braces are not needed A lock statement ensures that the section of code protected by the lock for the given object can be used only by the thread that obtains the lock All other threads are blocked until the lock is removed The lock is released when the block is exited The object you lock on is an object that represents the resource being synchronized In some cases, this will be an instance of the resource itself or simply an arbitrary instance of object that is being used to provide synchronization A key point to understand about lock is that the lock-on object should not be publically accessible Why Because it is possible that another piece of code that is outside your control could lock on the object and never release it In the past, it was common to use a construct such as lock(this) However, this only works if this refers to a private object Because of the potential for error and conceptual mistakes in this regard, lock(this) is no longer recommended for general use Instead, it is better to simply create a private object on which to lock This is the approach used by the examples in this chapter Be aware that you will still find many examples of lock(this) in legacy C# code In some cases, it will be safe In others, it will need to be changed to avoid problems The following program demonstrates synchronization by controlling access to a method called SumIt( ), which sums the elements of an integer array:

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// Use lock to synchronize access to an object using System; using SystemThreading; class SumArray { int sum; object lockOn = new object(); // a private object to lock on public int SumIt(int[] nums) { lock(lockOn) { // lock the entire method sum = 0; // reset sum for(int i=0; i < numsLength; i++) { sum += nums[i]; ConsoleWriteLine("Running total for " + ThreadCurrentThreadName + " is " + sum); ThreadSleep(10); // allow task-switch } return sum; } } } class MyThread { public Thread Thrd; int[] a; int answer; // Create one SumArray object for all instances of MyThread

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To answer this question, let B( t) be the number of bacteria at time t For convenience, let t = 0 correspond to 9:00 am and suppose that time is measured in hours Thus noon corresponds to t = 3 Equation ( ) guarantees that B( t) = P eK t for some undetermined constants P and K We also know that 5000 = B( 0) = P eK 0 = P We see that P = 5000 and B( t) = 5000 eK t We still need to solve for K Since the population tends to double in four hours, there will be 10, 000 bacteria at time t = 4; hence 10000 = B( 4) = 5000 eK 4

Thrilled means very happy and is a more exact and interesting choice Words such as very and good are weak and can almost always be replaced by a more precise and engaging term Modifying Phrases May Confuse Your Readers Misplaced modifying phrases sometimes result in odd, even humorous interpretations Be certain to position the modifying word or phrase as close as possible to the term that is being modi ed Consider, for example:

Part II:

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static SumArray sa = new SumArray(); // Construct a new thread public MyThread(string name, int[] nums) { a = nums; Thrd = new Thread(thisRun); ThrdName = name; ThrdStart(); // start the thread } // Begin execution of new thread void Run() { ConsoleWriteLine(ThrdName + " starting"); answer = saSumIt(a); ConsoleWriteLine("Sum for " + ThrdName + " is " + answer); ConsoleWriteLine(ThrdName + " terminating"); } } class Sync { static void Main() { int[] a = {1, 2, 3, 4, 5}; MyThread mt1 = new MyThread("Child #1", a); MyThread mt2 = new MyThread("Child #2", a); mt1ThrdJoin(); mt2ThrdJoin(); } }

Here is sample output from the program (The actual output you see may vary slightly)

Sketch the set of points = {( x, y) : y = 3} Sketch the set of points k = {( x, y) : x = 4}

Child #1 starting Running total for Child Child #2 starting Running total for Child Running total for Child Running total for Child Running total for Child Running total for Child Sum for Child #1 is 15 Child #1 terminating Running total for Child Running total for Child Running total for Child Running total for Child Sum for Child #2 is 15 Child #2 terminating #1 is 1 #1 #1 #1 #1 #2 is is is is is 3 6 10 15 1

#2 #2 #2 #2

3 6 10 15

23:

The set consists of all points with y-coordinate equal to 3 This is the set of all points that lie 3 units above the x-axis We exhibit in Figure 19 It is a horizontal line

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A counselor with a drinking problem It would be better to write:

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